Find size of segments in a seglist?

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Tue, 2011-07-05 20:33
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ChrisH
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Find size of segments in a seglist?
Is it possible to find the size (in bytes) of a segment in a seglist? The seglist would come from LoadSeg(), but might contain 68k & other non-OS4-native segments. (I am a total novice regarding seglists, but I gather you can walk the list by treating the top of the segment as a pointer.)
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Wed, 2011-07-06 14:51
thomas
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On 68k the seglist looks like
On 68k the seglist looks like this: ULONG size; /* size in longwords, i.e. divided by 4 */ BPTR next; /* BPTR to next segment. Multiply by 4 to get CPTR (use BADDR() macro) */ ULONG data[n]; /* contents of segment */ LoadSeg() returns a BPTR to "next". The "next" pointer also points to the "next" field of the next segment (or 0 if this one is the last one). For OS4 see struct PseudoSegList in dos/dosextens.h. The comments say that it has a size field before it just like the 68k seglist.
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Wed, 2011-07-06 23:58
(Reply to #2)
ChrisH
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Thanks! So if I treat a
Thanks! So if I treat a segment as an array of "long", where "next" is index 0, then the size is at index "-1", right?
Author of the PortablE programming language. I love using Amiga OS4.1 on my X1000 & Sam440 :-D
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Thu, 2011-07-07 15:33
(Reply to #3)
thomas
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Should be unsigned long, but
Should be unsigned long, but yes, that's right. Note that the size is given in number of ULONGs, not in number of bytes.
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Mon, 2011-07-11 00:30
(Reply to #4)
ChrisH
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Quote:Note that the size is
Note that the size is given in number of ULONGs, not in number of bytes.
Ah, thanks, I would have got that wrong.
Author of the PortablE programming language. I love using Amiga OS4.1 on my X1000 & Sam440 :-D
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Sun, 2014-11-30 00:54
(Reply to #5)
amiganaut
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@thomas: Note that the size
@thomas:
Note that the size is given in number of ULONGs, not in number of bytes.
Are you sure that this information is correct? AFAICS the size is in bytes and not in ULONGs under OS3.
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Tue, 2014-12-09 15:46
(Reply to #6)
thomas
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Are you sure that this
Are you sure that this information is correct?
No, I am not ;-) Looking into another program from me it seems you are right, the length is in bytes.
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